A string on a musical instrument is $50 cm$ long and its fundamental frequency is $270 Hz$. If the desired frequency of $1000 Hz$ is to be produced, the required length of the string is .... $cm$
A$13.5$
B$2.7$
C$5.4$
D$10.3$
Easy
Download our app for free and get started
A$13.5$
a (a) $n \propto \frac{1}{l} \Rightarrow \frac{{{l_2}}}{{{l_1}}} = \frac{{{n_1}}}{{{n_2}}} $
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A narrow tube is bent in the form of a circle of radius $R,$ as shown in the figure. Two small holes $S$ and $D$ are made in the tube at the positions right angle to each other. A source placed at $S$ generated a wave of intensity $I_0$ which is equally divided into two parts : One part travels along the longer path, while the other travels along the shorter path. Both the part waves meet at the point $D$ where a detector is placed If the minima is formed at the detector then, the magnitude of wavelength $\lambda$ of the wave produced is given by
A tuning fork $A$ produces $4$ beats/sec with another tuning fork $B$ of frequency $320 Hz$. On filing the fork $A$, $4$ beats/sec are again heard. The frequency of fork $A$, after filing is ....$Hz$
A wave is represented by $x=4 \cos \left(8 t-\frac{y}{2}\right)$, where $x$ and $y$ are in metre and $t$ in second. The frequency of the wave $\left(\right.$ in $^{-1}$ ) is .........
A tuning fork of frequency $480\, Hz$ is used in an experiment for measuring speed of sound $(\nu )$ in air by resonance tube method. Resonance is observed to occur at two successive lengths of the air column, ${\ell _1} = 30\,cm$ and ${\ell _2} = 70\,cm$. Then $\nu$ is equal to ..... $ms^{-1}$
If $n _{1}, n_{2}$ and $n _{3}$ are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency $n$ of the string is given by
A transverse harmonic wave on a string is described by $y = 3 \sin \,(36t + 0.018x + \frac{\pi}{4})$ where $x$ and $y$ are in $cm$ and $t$ in $s$. The least distance between two sucessive crests in the wave is .... $m$