A tuning fork of frequency $480\, Hz$ is used in an experiment for measuring speed of sound $(\nu )$ in air by resonance tube method. Resonance is observed to occur at two successive lengths of the air column, ${\ell _1} = 30\,cm$ and ${\ell _2} = 70\,cm$. Then $\nu$ is equal to ..... $ms^{-1}$
JEE MAIN 2019, Medium
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$v=2 f(l_2-l_1)$
$v=2 \times 480 \times(70-30) \times 10^{-2}$
$v=960 \times 40 \times 10^{-2}$
$\mathrm{v}=38400 \times 10^{-2} \mathrm{m} / \mathrm{s}$
$v=384 \mathrm{m} / \mathrm{s}$
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