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STD 11 - 6.2. Equilibrium - II (icon Equilibrium) — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 6.2. Equilibrium - II (icon Equilibrium)4 Marks
MCQ
A student needs to prepare a buffer solution of propanoic acid and its sodium salt with $pH$ $4.$ The ratio of $\frac{\left[ CH _{3} CH _{2} COO ^{-}\right]}{\left[ CH _{3} CH _{2} COOH \right]}$ required to make buffer is .....

Given : $K _{ a }\left( CH _{3} CH _{2} COOH \right)=1.3 \times 10^{-5}$

  • A
    $0.03$
  • ✓
    $0.13$
  • C
    $0.23$
  • D
    $0.33$
✓

Answer

Correct option: B.
$0.13$
b
$pH = pK _{ a }+\log \frac{[\text { Salt }]}{[\text { Acid }]}$

$4=5-\log 1.3+\log \frac{\left[ CH _{3} CH _{2} COO ^{-}\right]}{\left[ CH _{3} CH _{2} COOH \right]}$

$\log \frac{\left[ CH _{3} CH _{2} COO ^{-}\right]}{\left[ CH _{3} CH _{2} COOH \right]}=\log 1.3-1=\log \frac{1.3}{10}$

$\frac{\left[ CH _{3} CH _{2} COO ^{-}\right]}{\left[ CH _{3} CH _{2} COOH ^{-}\right]}=0.13$

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