- A$\angle\text{i} = \angle\text{e} > \angle\text{r}$
- B$\angle\text{i} > \angle\text{r} > \angle\text{e}$
- C$\angle\text{i} = \text{Zr} < \text{Ze}$
- D$\angle\text{i} = \angle\text{e}< \angle\text{r}$
Explanation:
Since the emergent ray is always parallel to the incident ray, therefore the angle of incidence is always equal to the angle of emergence i.e.
$\angle\text{i}=\angle\text{e}\ .....(\text{i})$
Also, when a light ray travels from rarer to denser medium, it bends towards the normal. Hence
$\angle\text{i}>\angle\text{r}\ .....(\text{ii})$
From (i) and (ii), we get
$\angle\text{i}=\angle\text{e}>\angle\text{r}$
Hence, the correct answer is $\angle\text{i}=\angle\text{e}>\angle\text{r}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
