A student uses a lens of focal length -50cm. What is the nature of the lens and its power?
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Since the focal length is negative, therefore the lens is concave lens because the focal length of concave lens is negative. P (in diopter) $=\frac{1}{\text{f (in meters)}}$When $\text{f}=-50\text{cm}=-0.5\text{m}$
$\text{P}=\frac{1}{\text{f (in m)}}=\frac{1}{-0.5}=-2\text{D}$
Lens is concave.
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