- ✓$[AV^2D]$
- B$[A^2VD]$
- C$[AVD^2]$
- D$[A^0VD]$
$=(\text { Area } \times \text { length }) \times$ density $\times \frac{\mathrm{L}}{\mathrm{T}^{2}}$
$\left[\text { velocity } \mathrm{v}^{2}=\frac{\mathrm{L}^{2}}{\mathrm{T}^{2}}\right]$
$=\left[\mathrm{Av}^{2} \mathrm{D}\right]$
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Reason : For a dark fringe intensity is zero.

statement$-1$ : The temperature dependence of resistance is usually given as $R=R_{0}(1+\alpha \Delta t)$. The resistance of a wire changes from $100\; \Omega$ to $150\; \Omega$ when its temperature is increased from $27^{\circ} C$ to $227^{\circ} C$. This implies that $\alpha=2.5$ $\times 10^{-3} /{ }^{\circ} C$
statement$-2\;: R=R_{0}(1+\alpha \Delta t)$ is valid only when the change in the temperature $\Delta T$ is small and $\Delta R=\left(R-R_{0}\right) < < R_{0}$
