A system is oscillating with undamped simple harmonic motion. Then the
Advanced
Download our app for free and get startedPlay store
Total energy of system is $P E+K E$ remains constant, when system is at mean position, $x=0 \Rightarrow P E=0,$ and $K E=$ max. so average of total energy is equal to total energy at mean position which is maximum kinetic energy.

similarly, at extreme points, $K E=0$ and $P E=$ $max.$

so average of total energy is equal to total energy at extreme position which is maximum potential energy.

Now, if $x=A \sin \omega t \Rightarrow v=A \omega \cos \omega t$

Maximum velocity is $v_{\max }=A \omega$ and $\mathrm{rms}$ value of velocity is $A \omega / \sqrt{2}=v_{\max } / \sqrt{2}(\because \mathrm{rms}$ value of $\cos \theta$ is $1 / \sqrt{2}$ )

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    The maximum velocity of a simple harmonic motion represented by $y = 3\sin \,\left( {100\,t + \frac{\pi }{6}} \right)$is given by
    View Solution
  • 2
    A particle performs simple harmonic oscillation of period $T$ and the equation of motion is given by; 

    $x = a\,\sin \,\left( {\omega t + \pi /6} \right)$

    After the elapse of what fraction of the time period the velocity of the particle will be equal to half of its maximum velocity?

    View Solution
  • 3
    A uniform rod of length $L$ and mass $M$ is pivoted at the centre. Its two ends are attached to two springs of equal spring constants $k$. The springs are fixed to rigid supports as shown in the figure, and the rod is free to oscillate in the horizontal plane. The rod is gently pushed through a small angle $\theta$ in one direction and released. The frequency of oscillation is
    View Solution
  • 4
    A particle executes simple harmonic motion with an amplitude of $4 \,cm$. At the mean position the velocity of the particle is $10\, cm/s$. The distance of the particle from the mean position when its speed becomes $5 \,cm/s$ is
    View Solution
  • 5
    The displacement $y(t) = A\,\sin \,(\omega t + \phi )$ of a pendulum for $\phi = \frac {2\pi }{3}$ is correctly represented by
    View Solution
  • 6
    One-forth length of a spring of force constant $K$ is cut away. The force constant of the remaining spring will be
    View Solution
  • 7
    The maximum velocity of a body undergoing $S.H.M$. is $0.2\,m/s$ and its acceleration at $0.1\,m$ from the mean position is $0.4\,m/s^2$. The amplitude of the $S.H.M.$ is .... $m$
    View Solution
  • 8
    A tunnel is dug in the earth across one of its diameter. Two masses $‘m’\,\& \,‘2m’$ are dropped from the ends of the tunnel. The masses collide and stick to each other and perform $S.H.M.$ Then amplitude of $S.H.M.$ will be : [$R =$ radius of the earth]
    View Solution
  • 9
    If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is $\frac{x}{2}$ times its original time period. Then the value of $x$ is:
    View Solution
  • 10
    If a spring of stiffness $k$ is cut into two parts $A$ and $B$ of length $l_{A}: l_{B}=2: 3$, then the stiffness of spring $A$ is given by
    View Solution