MCQ
A system is taken through a cyclic process represented by a circle as shown. The heat absorbed by the system is
- A$\pi \times 10^3 J$
- ✓$\frac{\pi}{2} J$
- C$4 \pi \times 10^2 J$
- D$\pi J$
✓
Answer
Correct option: B.
$\frac{\pi}{2} J$
(b) In cyclic process $\Delta Q=$ Work done $=$ Area inside the closed curve.Treat the circle as an ellipse of area $=\frac{\pi}{4}\left(P_2P_1\right\left(V_2V_1\right[\Rightarrow \Delta Q=\frac{\pi}{4}\left\{(150-50) \times 10^3\right\}=\frac{\pi}{
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