Two identical cylindrical vessels with their bases at same level, each contains a liquid of density $d$ . The height of the liquid in one vessel is $ h_1$ and that in the other vessel is $h_2$ . The area of either base is $A$ . The work done by gravity in equalizing the levels when the two vessels are connected is
A$(h_1 -h_2)gd$
B$(h_1 -h_2)gAd$
C$\frac {1}{2}(h_1 -h_2)^2gAd$
D$\frac {1}{4}(h_1 -h_2)^2gAd$
Medium
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D$\frac {1}{4}(h_1 -h_2)^2gAd$
d Work done = initial potential energy -final potential energy
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