Download App

11. thermodynamics — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics11. thermodynamics1 Mark
MCQ
A thermodynamic system is taken from an original state $A$ to an intermediate state $B$ by a linear process as shown in the figure. It's volume is then reduced to the original value from $B$ to $C$ by an isobaric process. The total work done by the gas from $A$ to $B$ and $B$ to $C$ would be :
  • A
     $33800 \mathrm{~J}$
  • B
    $2200 \mathrm{~J}$
  • ✓
     $800 \mathrm{~J}$
  • D
     $1200 \mathrm{~J}$
✓

Answer

Correct option: C.
 $800 \mathrm{~J}$
c
Work done $\mathrm{AB}=\frac{1}{2}(8000+6000)$ Dyne $/ \mathrm{cm}^2 \times$ $4 \mathrm{~m}^3=\left(6000 \mathrm{Dyne} / \mathrm{cm}^2\right) \times 4 \mathrm{~m}^3$

Work done $\mathrm{BC}=-\left(4000\right.$ Dyne $\left./ \mathrm{cm}^2\right) \times 4 \mathrm{~m}^3$

Total work done $=2000$ Dyne $/ \mathrm{cm}^2 \times 4 \mathrm{~m}^3$

$=2 \times 10^3 $  $\times \frac{1}{10^5} \frac{\mathrm{N}}{\mathrm{cm}^2} \times 4 \mathrm{~m}^3 $

$ =2 \times 10^{-2} \times \frac{\mathrm{N}}{10^{-4} \mathrm{~m}^2} \times 4 \mathrm{~m}^3 $

$ =2 \times 10^2 \times 4 \mathrm{Nm}=800 \mathrm{~J}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 11. thermodynamics→11. thermodynamics — all question types→Physics STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Two masses of  $1\,kg$  and  $2\,kg$ respectively are connected by a massless spring as shown in figure. A force of  $20\,N$  acts on the  $2\,kg$  mass at the instant when the $1\, kg$  mass has an acceleration of  $10\,ms^{-2}$  towards right, the acceleration of the $2\,\,kg$  mass is ......... $ms^{-2}$
→
A ball is thrown from the ground to clear a wall $3\,m$ high at a distance of $6\,m$ and falls $18\,m$ away from the wall, the angle of projection of ball is
→
'$n$' moles of an ideal gas undergoes a process $A \rightarrow B$ as shown in the figure. The maximum temperature of the gas during the  process will be
→
In a given process for an ideal gas, $dW = 0$ and $dQ < 0.$ Then for the gas
→
The displacement of a particle is represented by the following equation $s = 2t^3 + 7t^2 + 5t + 8$ where $s$ is in metres and $t$ in seconds. The acceleration of the particle at $t = 1\ s$ is:
→
Surface tension is due to
→
The displacement of a particle undergoing $SHM$ of time period $T$ is given by $x(t) = x_m\,cos\, (\omega t + \phi )$. The particle is at $x = -x_m$ at time $t = 0$. The particle is at $x = + x_m$ when
→
Two rays A and B being reflected by a mirror and going as A' and B'. The mirror:
→
Three conducting rods of same material and cross section are shown in figure. Temperature at $A,D$ and $C$ are maintained at $20\ ^oC, 90\ ^oC$ and $0\ ^oC$. The ratio of lengths of $BD$ and $BC$ if there is no heat. Flows in $AB$ is
→
Two sound waves having a phase difference of $60°$ have path difference of
→