$=3 i_{0}^{2} R t_{0}+9 i_{0}^{2} R t_{0}+i_{0}^{2} R t_{0}=13 i_{0}^{2} R t_{0}$
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$62.5 \times {10^{18}}$ electrons per second are flowing through a wire of area of cross-section $0.1\,{m^2}$, the value of current flowing will be ............ $A$
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