A triode has a mutual conductance of 2 times 10^{-3} mho and an amplification factor of 50. The anode is connected through a resistance of

Q: A triode has a mutual conductance of $2 \times 10^{-3} mho$ and an amplification factor of $50.$ The anode is connected through a resistance of $25 \times 10^3$ ohms to a $250$ volts supply. The voltage gain of this amplifier is

$ \text { Using } A_v=\frac{\mu}{1+\frac{r_p}{R_L}} \text { and } \mu=r_p \times g_m$ $\Rightarrow r_p=\frac{\mu}{g_m}=\frac{50}{2 \times 10^{-3}}=25 \times 10^3 \Omega $ $ \therefore A_v=\frac{50}{1+\frac{25 \times 10^3}{25 \times 10^3}}=25 .$

MCQ

CBSE - English Medium

A triode has a mutual conductance of $2 \times 10^{-3} mho$ and an amplification factor of $50.$ The anode is connected through a resistance of $25 \times 10^3$ ohms to a $250$ volts supply. The voltage gain of this amplifier is

A$50$
B$25$
C$100$
D$12.5$

[MP PMT 1989]

STD 12 Science
JEE physics
Electronics
NCERT

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