A tuning fork with frequency $800 \;\mathrm{Hz}$ produces resonance in a resonance column tube with upper end open and lower end closed by water surface. Surface. Successive resonance are observed at length $9.75 \;\mathrm{cm}, 31.25\; \mathrm{cm}$ and $52.75\; \mathrm{cm} .$ The speed of sound in air is ......$m/s$
NEET 2019, Medium
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Here $\lambda=2\left(l_{2}-l_{1}\right)$
where $l_{1}=9.75 \mathrm{cm}, l_{2}=31.25 \mathrm{cm}$
so $\mathrm{v}=2 \mathrm{n}\left(l_{2}-l_{1}\right)=2 \times 800(31.25-9.75)=344 \mathrm{m} / \mathrm{s}$
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