A uniform conducting wire $A B C$ has a mass of $10 \,g$. A current of $2 \,A$ flows through it. The wire is kept in a uniform magnetic field $B=2 T$. The acceleration of the wire will be ............. $ms ^{-2}$
Medium
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(b)
Force on wire $A B C$ will be same as force on wire $A C$, using $F=i(\vec{l} \times \vec{B})$
$F=2\left(\frac{3}{100}\right)(2) \sin 90^{\circ}$
$=12 \times 10^{-2} \,N$
$a=\frac{F}{m}=\frac{12 \times 10^{-2}}{10^{-2}}=12 \,m / s ^2$
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