A uniformly tapering vessel is filled with a liquid of density $900 kg/m^3.$ The force that acts on the base of the vessel due to the liquid is ......... $N$. $(g = 10\,m{s^{ - 2}})$
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(b)Force acting on the base
$F = P \times A = hdgA$$ = 0.4 \times 900 \times 10 \times 2 \times {10^{ - 3}} = 7.2N$
$F = P \times A = hdgA$$ = 0.4 \times 900 \times 10 \times 2 \times {10^{ - 3}} = 7.2N$
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