A wall consists of alternating blocks of length $d$ and coefficient of thermal conductivity $K_{1}$ and $K_{2}$ respectively as shown in figure. The cross sectional area of the blocks are the same. The equivalent coefficient of thermal conductivity of the wall between left and right is
NEET 2017, Medium
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In parallel
$K_{eq}=\frac{ K _{1} A _{1}+ K _{2} A _{2}}{ A _{1}+ A _{2}}$
Cross sectional Area $A _{1}= A _{2}= A$, for all rods.
for any two rods having same coefficient, $K _{1}$ the resultant is also $K _{1}$
so the above combination will reduce to a combination having just two rods one with $K _{1}$ and another with $K _{2}$
So net coefficient of conductivity will be $K=\frac{K_{1}+K_{2}}{2}$
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