A wave travelling along positive $x-$ axis is given by $y = A\sin (\omega \,t - kx)$. If it is reflected from rigid boundary such that $80\%$ amplitude is reflected, then equation of reflected wave is
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(b) On getting reflected from a rigid boundary the wave suffers
Hence if ${y_{incident}}$= $A\sin (\omega t - kx)$
then ${y_{reflected}} = (0.8A)$ $\sin \left\{ {\omega t - k( - x) + \pi } \right\}$
$ = - 0.8A\sin (\omega t + kx)$ an additional phase change of $\pi $.
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