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The length of wire becomes $l_1$ and $l_2$ when $100\,N$ and $120\,N$ tensions are applied respectively. If $10l_2=11l_1$, the natural length of wire will be $\frac{1}{x} l_1$. Here the value of $x$ is ........
On all the six surfaces of a unit cube, equal tensile force of $F$ is applied. The increase in length of each side will be ($Y =$ Young's modulus, $\sigma $= Poission's ratio)
Wires $A$ and $B$ are made from the same material. $A$ has twice the diameter and three times the length of $B.$ If the elastic limits are not reached, when each is stretched by the same tension, the ratio of energy stored in $A$ to that in $B$ is
Auniform rod rotating in gravity free region with certain constant angular velocity. The variation of tensile stress with distance $x$ from axis of rotation is best represented by which of the following graphs.
The breaking stress of aluminium is $7.5 \times 10^7 \,Nm ^{-2}$. The greatest length of aluminium wire that can hang vertically without breaking is $......... \times 10^3 \,m ($Density of aluminium is $2.7 \times 10^3 \,kg m ^{-3} )$
On increasing the length by $0.5\, mm$ in a steel wire of length $2\, m$ and area of cross-section $2\,m{m^2}$, the force required is $[Y$ for steel$ = 2.2 \times {10^{11}}\,N/{m^2}]$