A wire is suspended by one end. At the other end a weight equivalent to $20\, N$ force is applied. If the increase in length is $1.0\, mm$, the increase in energy of the wire will be ....... $joule$
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(a) Increase in energy $ = \frac{1}{2} \times 20 \times 1 \times {10^{ - 3}} = 0.01J$
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