Let tension be $T$
$f_1=\sqrt{\frac{T}{\mu}} \times \frac{1}{2 l}=256$
$f_2=\sqrt{\frac{T+10}{\mu}} \times \frac{1}{2 l}=320$
$\sqrt{\frac{T}{T+10}}=\frac{256}{320}$
$\frac{T}{T+10}=\frac{(16)^2}{(16)^2 \times(20)^2}$
or $\frac{T}{T+10}=\frac{16^2}{(20)^2}$
or $400 T=256 T^2+2560$
or $144 T=2560$
or $T=\frac{2560}{144}$
or $T=\frac{2560}{16 \times 9}$
or $T=\frac{160}{9}$ Newton
$=\frac{16}{9} \,kg -w t$
Statement $-2$ : Due to the motion of source, wavelength of the sound waves (emitted by source) as received by stationary listener is affected.
Statement $-3$ : If receiver and source both are moving, the observed frequency must be different from the original frequency of source.
Treat motion of source or listener as always along a line joining them for all above cases.
$(A)$ The speed of sound determined from this experiment is $332 m s ^{-1}$
$(B)$ The end correction in this experiment is $0.9 cm$
$(C)$ The wavelength of the sound wave is $66.4 cm$
$(D)$ The resonance at $50.7 cm$ corresponds to the fundamental harmonic
