A wire of resistance $20 \Omega$ is divided into $10$ equal parts. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination is_______.0$\Omega$.
JEE MAIN 2024, Diffcult
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Each part has resistance $=2 \Omega$
$2$ parts are connected in parallel so, $R=1 \Omega$
Now, there will be 5 parts each of resistance $1 \Omega$, they are connected in series.
$\mathrm{R}_{\mathrm{xq}}=5 \mathrm{R}, \mathrm{R}_{\mathrm{sq}}=5 \Omega$
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