A wooden block of volume $1000\, cm^3$ is suspended from a spring balance. It weighs $12$ $N$ in air. It is suspended in water such that half of the block is below the surface of water. The reading of the spring balance is ...... $N$
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(d) Reading of the spring balance

= Apparent weight of the block

= Actual weight -upthrust

$ = 12 - {V_{in}}\sigma g$

$ = 12 - 500 \times {10^{ - 6}} \times {10^3} \times 10 = 12 - 5 = 7N.$

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