A wooden cube just floats inside water with a $200 \,gm$ mass placed on it. When the mass is removed, the cube floats with its top surface $2 \,cm$ above the water level. the side of the cube is ......... $cm$
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(c)
Mass $\times g=$ Volume of part of cube $\times \rho \times g$
$\Rightarrow 200 \times g=L^2\left(2 \times \rho_w \times g\right)$
$\Rightarrow 100=L^2 \quad\left\{\because \rho_w=1\right\}$
$\Rightarrow 10 \,cm =L$
From the two figures we can see that the $200 \,gm$ block is provided with required buoyant force but a part of cube which is afloat in $2^{\text {nd }}$ figure.
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