\(10 \mathrm{~g} \sin 53^{\circ}-\mu(10 \mathrm{~g}) \cos 53^{\circ}-\mathrm{T}=10 \times 2\)

\(\mathrm{~T}=80-15-20\)

\(\mathrm{~T}=45 \mathrm{~N}\)

For \(\mathrm{m}\) block

\(\mathrm{T}-\mathrm{mg} \sin 37^{\circ}-\mu \mathrm{mg} \cos 37^{\circ}=\mathrm{m} \times 2\)

\(45=10 \mathrm{~m}\)

\(\mathrm{~m}=4.5 \mathrm{~kg}\)