Electric field at \(A\) due to \(+Q\) at \(B\) is given by, \(E_{A B}\) in the direction of \(X\).
Also, electric field at \(C\) is given by \(E _{ AC }\) in the direction of \(Z\).
Hence, the resultant will be the sum of these two electric field and will be given by the parallelogram law of vector addition and will be in the direction of AY.
[ અત્રે $\hat{i}, \hat{j}$ અને $\hat{k}$ એ અનુક્રમે $x, y$ અને $z-$ અક્ષોની દિશામાં એકમ સદિશ છે.]