$\left( i \right)\,2F{e_2}{O_3}\left( s \right) \to 4Fe\left( s \right) + 3{O_2}\left( g \right)$
${\Delta _r}{G^o} = + 1487.0\,kJ\,mo{l^{ - 1}}$
$\left( {ii} \right)\,2CO\left( g \right) + {O_2}(g) \to 2C{O_2}\left( g \right)$
${\Delta _r}{G^o} = - 514.4\,kJ\,mo{l^{ - 1}}$
તો નીચેની પ્રક્રિયા માટે મુક્ત ઊર્જા ફેરફાર $\Delta_rG^o$ .....$kJ\, mol^{-1}$
$\,2F{e_2}{O_3}\left( s \right) + 6CO\left( g \right) \to 4Fe\left( s \right) + 6C{O_2}\left( g \right)$
\({\Delta _r}{G^o} = + 1487.0\,kJ\,mo{l^{ - 1}}\)
\((ii)\,2CO(g) + {O_2}(g) \to 2C{O_2}(g);\)
\({\Delta _r}{G^o} = - 514.4\,kJ\,mo{l^{ - 1}}\)
Multiple reaction \((ii)\) with \(3\),we get
\((iii)\,6CO(g) + 3{O_2}(g) \to 6C{O_2}(g);\)
\({\Delta _r}{G^o} = 3 \times - 514.4 = - 1543.2\,kJ\,mo{l^{ - 1}}\)
When we add reaction \((i)\) and reaction \((iii)\), we get reaction \((iv)\)
\((iv)\,2F{e_2}{O_3}(s) + 6CO(g) \to 4Fe(s) + 6C{O_2}(g)\)
Free energy change, \({\Delta _r}{G^o}\) for the reaction will be
\(1487.0 - 1543.2 = - 56.2\,kJ\,mo{l^{ - 1}}\)
$(i)$ $Hg +$ $\frac{1}{2}O_2$ $\rightarrow$ $HgO + 21700 \,cal …….$
$(ii)$ $Zn + HgO$ $\rightarrow$$ ZnO + Hg$ માટે પ્રક્રિયા ઉષ્મામાં ($\Delta H$)......$cal$ થશે.