Hybridization of \(\mathrm{Si}-\mathrm{s} p^{3},\) bond angle \(=109\,^o28'\)
\(\angle Cl-\text{N}-\text{Cl}\) in \(NCl_3\) is greater than \(\angle \text{Cl}-\text{P}-\text{Cl}\) in \(\mathrm{PCl}_{3}\) because partidpation of \(s-\) orbital in the hybridization decreases from \(NCl_3\) to \(PCl_3\)
Figure \((2)\)
\(\angle \text{Cl}-\text{P}-\text{Cl}\) in \(\text{PC}{{\text{l}}_{3}}>\angle \text{H}-\text{Sb}-\text{H}\) in \(\mathrm{SbH}_{3},\) as in \(\mathrm{SbH}_{3}\), bond pairs are formed by overlapping of almost pure \(p-\) orbitals.
\(\angle \text{H}-\text{Sb}-\text{H}\) in \(\text{Sb}{{\text{H}}_{3}}<\angle \text{H}-\text{Te}-\text{H}\) in \(\mathrm{H}_{2}Te\) because two lone pairs are present on \(Te\) while at \(\mathrm{Sb}\) there is one lone pair.
$A, B$ અને $C$ શું હશે ?
કોડ | લીસ્ટ $I$ | કોડ | લીસ્ટ $I$ |
$(A)$ | $XeF_4$ | $(1)$ | ડીસ્ટટ્રેડઅષ્ટફલકીય |
$(B)$ | $XeF_6$ | $(2)$ | ચતુષફલકીય |
$(C)$ | $XeO_3$ | $(3)$ | સમતલીય ચોરસ |
$(D)$ | $XeO_4$ | $(4)$ | ત્રિકોણીય |
પિરમીડલ |