d
\({V_A} - {V_B} = 1000\,V\)\({C_{eq}} = \frac{{2 \times 3}}{{2 + 3}} = \frac{6}{5}\,\mu F\) \(Q = {C_{eq}} \times ({V_A} - {V_B})\) \( = \frac{6}{5} \times 1000 = 1200\,\mu C\) \({V_A} - {V_C} = \frac{{1200}}{2} = 600\,V\) \(==>\) \(1000 - {V_C} = 600\) \(==>\) \({V_c} = 400\ V\)