$\left[ Ni \left( H _2 O \right)_6\right] Cl _2 \Rightarrow$ Gives $2$ moles $AgCl$
$\left[ Pt \left( NH _3\right)_2 Cl _2\right] \Rightarrow$ Gives No $AgCl$
$\left[ Pd \left( NH _3\right)_4\right] Cl _2 \Rightarrow$ Gives $2$ moles $AgCl$
Total number of moles of $AgCl =5$ mole.
($en=$ એથીલીનડાયએમાઈન )