Question
ABCD is a parallelogram in which $\angle\text{A}=70^\circ$ Compute $\angle\text{B},\angle\text{C}$ and $\angle\text{D}$.

Answer

In a parallelogram ABCD$\angle\text{A}=70^\circ$
$\angle\text{A}+\angle\text{B}=180^\circ$ [Since, adjacent angles are supplementary]
$70^\circ+\angle\text{B}=180^\circ$ $[\because\angle\text{A}=70^\circ]$
$\angle\text{B}=1800-70^\circ$
$\angle\text{B}=110^\circ$
In a parallelogram opposite sides are equal.$\angle\text{A}=\angle\text{C}=70^\circ$
$\angle\text{B}=\angle\text{D}=110^\circ$

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