MCQ
Above conversion can be achieved by


- A$Zn(Hg), HCl$
- ✓$NH_2 - NH_2 /KOH/ \Delta$
- C$LiAlH_4$
- D$H_2/Ni$

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($A$) It will deflect up by an angle $\tan ^{-1}\left[\frac{\left(n_2^2-n_1^2\right) d}{2 h}\right]$
($B$) It will deflect up by an angle $\tan ^{-1}\left[\frac{\left(n_2-n_1\right) d}{h}\right]$
($C$) It will not deflect.
($D$) The deflection angle depends only on $\left(n_2-n_1\right)$ and not on the individual values of $n_1$ and $n_2$.

