MCQ
According to the Bohr theory, which of the following transitions in the hydrogen atom will give rise to the least energetic photon ?
- A$n = 6$ to $ n = 1$
- B$n = 5$ to $n = 4$
- ✓$n = 6 $ to $n = 5$
- D$n = 5$ to $n = 3$
✓
Answer
Correct option: C.
$n = 6 $ to $n = 5$
c
$E=\frac{h C}{\lambda}=h C R_{H}\left[\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right]$
$E=\frac{h C}{\lambda}=h C R_{H}\left[\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right]$
where $n_{2}>n_{1}$
Energy of photon obtained from the transition $n=6$ to $n=5$ will have least energy.
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