At 490 ,^oC, the equilibrium constant for the synthesis of HI is … - Vidyadip

MCQ

At $490\,^oC$, the equilibrium constant for the synthesis of $HI$ is $50$, the value of $K$ for the dissociation of $HI$ will be

A
$20$
B
$2$
C
$0.2$
✓
$0.02$

✓

Answer

Correct option: D.

$0.02$

(d) $K$ for dissociation of $HI =?$

${H_2} + {I_2}$ $ \rightleftharpoons $ $2HI$

${K_a} = 50$, ${K_b} = \frac{1}{{50}} = 0.02$

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