Question
Add: $\frac{-7}{24}$ and $\frac{-5}{48}$
✓
Answer
$\frac{-7}{24}$ and $\frac{-5}{48}$
$ =\frac{-7 \times 2}{24 \times 2}+\frac{-5 \times 1}{48 \times 1} $
$(\because$ L.C.M. of 24 and $48=48)$
$ =\frac{-14}{48}+\frac{-5}{48} $
$=\frac{(-14)+(-5)}{48}=\frac{-14-5}{48}=\frac{-19}{48}$
$ =\frac{-7 \times 2}{24 \times 2}+\frac{-5 \times 1}{48 \times 1} $
$(\because$ L.C.M. of 24 and $48=48)$
$ =\frac{-14}{48}+\frac{-5}{48} $
$=\frac{(-14)+(-5)}{48}=\frac{-14-5}{48}=\frac{-19}{48}$
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