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Exponents (Including Laws of Exponents) — MATHS STD 7 — Question

ICSE BoardEnglish MediumSTD 7MATHSExponents (Including Laws of Exponents)3 Marks
Question
Simplify and express the Solution in the positive exponent form:
$\frac{\left(2^3\right)^5 \times 5^4}{4^3 \times 5^2}$
✓

Answer


$\begin{aligned} & \frac{\left(2^3\right)^5 \times 5^4}{4^3 \times 5^2} \\ & =\frac{2^{3 \times 5} \times 5^4}{2^3 \times 2^2 \times 5^2} \\ & =\frac{2^{15} \times 5^4}{2^6 \times 5^2} \\ & =2^{15-6} \times 5^{4-2} \\ & =2^9 \times 5^2\end{aligned}$

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