Question
Add: $\frac{13}{-16}$ and $\frac{-11}{24}$
✓
Answer
$\begin{aligned} & \frac{13}{-16} \text { and } \frac{-11}{24}=\frac{-13}{16}+\frac{-11}{24} \\ & =\frac{-13 \times 3}{16 \times 3}+\frac{-11 \times 2}{24 \times 2} \\ & (\because \text { L.C.M. of } 16 \text { and } 24=48) \\ & =\frac{-39}{48}+\frac{-22}{48} \\ & =\frac{(-39)+(-22)}{48}=\frac{-39-22}{48}=\frac{-61}{48}\end{aligned}$
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