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Fractions. — MATHS STD 6 — Question

Gujarat BoardEnglish MediumSTD 6MATHSFractions.2 Marks
Question
Add the fractions using Brahmagupta’s method:
$\frac{3}{4}+\frac{1}{3}$
✓

Answer


$\begin{array}{l}\frac{3}{4}+\frac{1}{3}=\frac{3}{4} \times \frac{3}{3}+\frac{1}{3} \times \frac{4}{4} \\ =\frac{9}{12}+\frac{4}{12}=\frac{9+4}{12} \\ =\frac{13}{12} \\ =1 \frac{1}{12}\end{array}$

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