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43 questions · self-marked practice — reveal the answer and mark yourself.

Question 12 Marks
Subtract as indicated:
$\frac{29}{7}$ from $\frac{45}{7}$
Answer
The denominators are same.
Therefore, $\frac{45}{7}-\frac{29}{7}=\frac{16}{7}=2 \frac{2}{7}$
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Question 22 Marks
Subtract as indicated:
$\frac{18}{5}$ from $\frac{23}{3}$
Answer
The denominators of the given fractions are 3 and 5.
The LCM of 3 and 5 is 15.
Then, $\frac{23}{3}=\frac{23 \times 5}{3 \times 5}=\frac{115}{15}, \frac{18}{5}=\frac{18 \times 3}{5 \times 3}=\frac{54}{15}$
Therefore, $\frac{23}{3}-\frac{18}{5}=\frac{115}{15}-\frac{54}{15}=\frac{61}{15}=4 \frac{1}{15}$
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Question 32 Marks
Subtract as indicated:
$\frac{13}{4}$ from $\frac{10}{3}$
Answer
The denominators of the given fractions are 3 and 4. The LCM of 3 and 4 is 12.
Then $\frac{13}{4}=\frac{13 \times 3}{4 \times 3}=\frac{39}{12}, \frac{10}{3}=\frac{10 \times 4}{3 \times 4}=\frac{40}{12}$
Therefore, $\frac{10}{3}-\frac{13}{4}=\frac{40}{12}-\frac{39}{12}=\frac{1}{12}$
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Question 42 Marks
subtraction using Brahmagupta’s method:
$\frac{2}{3}-\frac{1}{2}$
Answer
Given $\frac{2}{3}-\frac{1}{2}$
Here LCM of 3 and 2 is 6. Fractional unit for both fractions should be $\frac{1}{6}$
$\begin{aligned} \therefore \quad & \frac{2 \times 2}{3 \times 2}-\frac{1 \times 3}{2 \times 3} \\ & =\frac{4}{6}-\frac{3}{6} \\ & =\frac{4-3}{6} \\ & =\frac{1}{6}\end{aligned}$
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Question 52 Marks
subtraction using Brahmagupta’s method:
$\frac{5}{6}-\frac{4}{9}$
Answer
Given $\frac{5}{6}-\frac{4}{9}$
Hence LCM of 6 and 9 is 18. Fractional unit for both fractions should be $\frac{1}{18}$ then
$\begin{array}{l}\frac{5 \times 3}{6 \times 3}-\frac{4 \times 2}{9 \times 2} \\ =\frac{15}{18}-\frac{8}{18} \\ =\frac{15-8}{18} \\ =\frac{7}{18}\end{array}$
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Question 62 Marks
subtraction using Brahmagupta’s method:
$\frac{2}{5}-\frac{4}{15}$
Answer
Given $\frac{2}{5}-\frac{4}{15}$
Here LCM of 5 and 15 is 15. Fractional unit for both fractions should be $\frac{1}{15}$
$\begin{array}{l}\text { then } \frac{2 \times 3}{5 \times 3}-\frac{4 \times 1}{15 \times 1} \\ =\frac{6}{15}-\frac{4}{15} \\ =\frac{6-4}{15} \\ =\frac{2}{15}\end{array}$
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Question 72 Marks
subtraction using Brahmagupta’s method:
$\frac{8}{15}-\frac{3}{15}$
Answer
Given $\frac{8}{15}-\frac{3}{15}$
Fractional unit for both fractions is $\frac{1}{15}$ then $\frac{2 \times 3}{5 \times 3}-\frac{4 \times 1}{15 \times 1}$
$\begin{array}{l}\frac{8}{15}-\frac{3}{15}=\frac{8-3}{15} \\ =\frac{5}{15}=\frac{1}{3}\end{array}$
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Question 82 Marks
$\frac{10}{27}-\frac{1}{27} \frac{10}{27}-\frac{1}{27}$
Answer
$\begin{array}{l}\text { Here } \frac{10}{27}-\frac{1}{27} \\ =\frac{10-1}{27} \\ =\frac{9}{27}=\frac{1}{3}\end{array}$
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Question 92 Marks
$\frac{7}{9}-\frac{5}{9}$
Answer
Given $\frac{7}{9}-\frac{5}{9}$
As fractional unit is same i.e., $\frac{1}{9}$ we shall simply subtract numerators keeping fractional unit as $\frac{1}{9}$
$\begin{array}{l}\frac{7}{9}-\frac{5}{9} \\ =\frac{7-5}{9}=\frac{2}{9}\end{array}$
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Question 102 Marks
$\frac{5}{8}-\frac{3}{8}$
Answer
Given $\frac{5}{8}-\frac{3}{8}$
As fractional unit is same i.e., $\frac{1}{8}$ we shall simply subtract numerators keeping fractional unit as $\frac{1}{8}$
Then $\frac{5}{8}-\frac{3}{8}=\frac{5-3}{8}$
$=\frac{2}{8}=\frac{1}{4}$
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Question 112 Marks
Add the fractions using Brahmagupta’s method:
$\frac{9}{2}+\frac{5}{4}+\frac{7}{6}$
Answer

$\begin{array}{l}\frac{54}{12}+\frac{15}{12}+\frac{14}{12}=\frac{83}{12} \\ =\frac{11}{12}\end{array}$
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Question 122 Marks
Add the fractions using Brahmagupta’s method:
$\frac{2}{3}+\frac{4}{5}+\frac{3}{7}$
Answer

$\begin{array}{l}\frac{70}{105}+\frac{84}{105}+\frac{45}{105}=\frac{199}{105} \\ =1 \frac{94}{105}\end{array}$
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Question 132 Marks
Add the fractions using Brahmagupta’s method:
$\frac{3}{4}+\frac{1}{3}+\frac{1}{5}$
Answer

$\begin{array}{l}\frac{45}{60}+\frac{20}{60}+\frac{12}{60}=\frac{77}{60} \\ =1 \frac{17}{60}\end{array}$
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Question 142 Marks
Add the fractions using Brahmagupta’s method:
$\frac{8}{3}+\frac{2}{7}$
Answer
$\begin{array}{l}\frac{56}{21}+\frac{6}{21}=\frac{62}{21} \\ =2 \frac{20}{21}\end{array}$
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Question 152 Marks
Add the fractions using Brahmagupta’s method:
$\frac{9}{2}+\frac{5}{4}$
Answer

$\begin{array}{l}\frac{18}{4}+\frac{5}{4}=\frac{23}{4} \\ =5 \frac{3}{4}\end{array}$
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Question 162 Marks
Add the fractions using Brahmagupta’s method:
$\frac{3}{5}+\frac{5}{8}$
Answer

$\begin{array}{l}\frac{24}{40}+\frac{25}{40}=\frac{49}{40} \\ =\frac{9}{40}\end{array}$
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Question 172 Marks
Add the fractions using Brahmagupta’s method:
$\frac{4}{5}+\frac{2}{3}$
Answer

$\begin{array}{l}\frac{12}{15}+\frac{10}{15}=\frac{22}{15} \\ =1 \frac{7}{15}\end{array}$
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Question 182 Marks
Add the fractions using Brahmagupta’s method:
$\frac{2}{3}+\frac{4}{5}$
Answer

$\begin{array}{l}\frac{10}{15}+\frac{12}{15}=\frac{22}{15} \\ =1 \frac{7}{15}\end{array}$
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Question 192 Marks
Add the fractions using Brahmagupta’s method:
$\frac{3}{4}+\frac{1}{3}+\frac{1}{5}$
Answer

$\begin{array}{l}\frac{45}{60}+\frac{20}{60}+\frac{12}{60} \\ =\frac{77}{60} \\ =1 \frac{17}{60}\end{array}$
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Question 202 Marks
Add the fractions using Brahmagupta’s method:
$\frac{2}{3}+\frac{2}{7}$
Answer

$\begin{array}{l}\frac{2}{3}+\frac{2}{7}=\frac{2}{3} \times \frac{7}{7}+\frac{2}{7} \times \frac{3}{3} \\ =\frac{14}{21}+\frac{6}{21}=\frac{20}{21}\end{array}$
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Question 212 Marks
Add the fractions using Brahmagupta’s method:
$\frac{2}{3}+\frac{5}{6}$
Answer

$\begin{array}{l}\frac{2}{3}+\frac{5}{6}=\frac{2}{3} \times \frac{2}{2}+\frac{5}{6} \\ \frac{4}{6}+\frac{5}{6}=\frac{9}{6}=\frac{3}{2} \\ =1 \frac{1}{2}\end{array}$
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Question 222 Marks
Add the fractions using Brahmagupta’s method:
$\frac{3}{4}+\frac{1}{3}$
Answer

$\begin{array}{l}\frac{3}{4}+\frac{1}{3}=\frac{3}{4} \times \frac{3}{3}+\frac{1}{3} \times \frac{4}{4} \\ =\frac{9}{12}+\frac{4}{12}=\frac{9+4}{12} \\ =\frac{13}{12} \\ =1 \frac{1}{12}\end{array}$
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Question 232 Marks
Add the fractions using Brahmagupta’s method:
$\frac{2}{7}+\frac{5}{7}+\frac{6}{7}$
Answer

$\begin{array}{l}\frac{2}{7}+\frac{5}{7}+\frac{6}{7} \\ =\frac{2+5+6}{7}=\frac{13}{7} \\ =1 \frac{6}{7}\end{array}$
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Question 242 Marks
Compare the fractions and justify your answer:
$\frac{9}{4}, \frac{5}{2}$
Answer
Given, fractions are $\frac{9}{4}, \frac{5}{2}$
LCM of 4 and 2 is 4
$\begin{array}{l}\frac{9}{4} \times \frac{1}{1}=\frac{9}{4} \\ \frac{5}{2} \times \frac{2}{2}=\frac{10}{4}\end{array}$
Clearly $\frac{9}{4}<\frac{10}{4}$ So, $\frac{9}{4}<\frac{5}{2}$
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Question 252 Marks
Compare the fractions and justify your answer:
$\frac{12}{5}, \frac{8}{5}$
Answer
Given fractions are $\frac{12}{5}$ and $\frac{8}{5}$
Clearly $\frac{12}{5}>\frac{8}{5}$
As denominators are same, so $\frac{12}{5}>\frac{8}{5}$
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Question 262 Marks
Compare the fractions and justify your answer:
$\frac{7}{10}, \frac{9}{14}$
Answer
Given fractions are $\frac{7}{10}$ and $\frac{9}{14}$
LCM of 10 and 14 is 70.
$\begin{array}{l}\frac{7}{10}=\frac{7}{10} \times \frac{7}{7}=\frac{49}{70} \\ \frac{9}{14}=\frac{9}{14} \times \frac{5}{5}=\frac{45}{70}\end{array}$
Clearly, $\frac{49}{70}>\frac{45}{70}$ So, $\frac{7}{10}>\frac{9}{14}$
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Question 272 Marks
Compare the fractions and justify your answer:
$\frac{4}{9}, \frac{3}{7}$
Answer
Given, fractions are $\frac{4}{9}$ and $\frac{3}{7}$
LCM of 9 and 7 is 63.
$\begin{array}{l}\frac{4}{9}=\frac{4}{9} \times \frac{7}{7}=\frac{28}{63} \\ \frac{3}{7}=\frac{3}{7} \times \frac{9}{9}=\frac{27}{63}\end{array}$
Clearly, $\frac{28}{63}>\frac{27}{63}$ So, $\frac{4}{9}>\frac{3}{7}$
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Question 282 Marks
Compare the fractions and justify your answer:
$\frac{8}{3}, \frac{5}{2}$
Answer
Given, fractions are $\frac{4}{9}$ and $\frac{3}{7}$
LCM of 3 and 2 is 6
$\frac{8}{3}=\frac{8}{3} \times \frac{2}{2}=\frac{16}{6}$ and $\frac{5}{2}=\frac{5}{2} \times \frac{3}{3}=\frac{15}{6}$
Clearly, $\frac{16}{6}>\frac{15}{6}$ So, $\frac{8}{3}>\frac{5}{2}$
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Question 292 Marks
Compare the fractions and justify your answer:
$\frac{9}{4}, \frac{5}{2}$
Answer
Given, fractions are $\frac{9}{4}, \frac{5}{2}$
LCM of 4 and 2 is 4
$\begin{array}{l}\frac{9}{4} \times \frac{1}{1}=\frac{9}{4} \\ \frac{5}{2} \times \frac{2}{2}=\frac{10}{4}\end{array}$
Clearly $\frac{9}{4}<\frac{10}{4}$ So, $\frac{9}{4}<\frac{5}{2}$
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Question 302 Marks
Compare the fractions and justify your answer:
$\frac{12}{5}, \frac{8}{5}$
Answer
Given fractions are $\frac{12}{5}$ and $\frac{8}{5}$
Clearly $\frac{12}{5}>\frac{8}{5}$
As denominators are same, so $\frac{12}{5}>\frac{8}{5}$
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Question 312 Marks
Compare the fractions and justify your answer:
$\frac{7}{10}, \frac{9}{14}$
Answer
Given fractions are $\frac{7}{10}$ and $\frac{9}{14}$
LCM of 10 and 14 is 70.
$\begin{array}{l}\frac{7}{10}=\frac{7}{10} \times \frac{7}{7}=\frac{49}{70} \\ \frac{9}{14}=\frac{9}{14} \times \frac{5}{5}=\frac{45}{70}\end{array}$
Clearly, $\frac{49}{70}>\frac{45}{70}$ So, $\frac{7}{10}>\frac{9}{14}$
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Question 322 Marks
Compare the fractions and justify your answer:
$\frac{4}{9}, \frac{3}{7}$
Answer
Given fractions are $\frac{4}{9}$ and $\frac{3}{7}$
LCM of 9 and 7 is 63.
$\begin{array}{l}\frac{4}{9}=\frac{4}{9} \times \frac{7}{7}=\frac{28}{63} \\ \frac{3}{7}=\frac{3}{7} \times \frac{9}{9}=\frac{27}{63}\end{array}$
Clearly, $\frac{28}{63}>\frac{27}{63}$ So, $\frac{4}{9}>\frac{3}{7}$
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Question 332 Marks
Compare the fractions and justify your answer:
$\frac{8}{3}, \frac{5}{2}$
Answer
Given fractions are $\frac{8}{3}$ and $\frac{5}{2}$
LCM of 3 and 2 is 6
$\frac{8}{3}=\frac{8}{3} \times \frac{2}{2}=\frac{16}{6}$ and $\frac{5}{2}=\frac{5}{2} \times \frac{3}{3}=\frac{15}{6}$
Clearly, $\frac{16}{6}>\frac{15}{6}$ So, $\frac{8}{3}>\frac{5}{2}$
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Question 342 Marks
How many whole units are there in $\frac{4}{3}$ and in $\frac{7}{3} ?$
Answer

$\frac{4}{3}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=1+\frac{1}{3}$
So, there are 1 whole unit in $\frac{4}{3}$.
$\frac{7}{3}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=2+\frac{1}{3}$
So, there are 2 whole units in $\frac{7}{3}$.
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Question 352 Marks
How many whole units are there in $\frac{7}{2} ?$
Answer

$\frac{7}{2}=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}=3+\frac{1}{2}$
So, there are 3 whole units in $\frac{7}{2}$.
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Question 372 Marks
What is the length of the pink line and black line shown below? The distance between 0 and 1 is 1 unit long, and it is divided into two equal parts. The length of each part is $\frac{1}{2}$. So the pink line is y units long. Write the fraction that gives the length of the black line in the box.
Image
Answer
Length of black line is $\frac{1}{2}$;
Length of black line is $\frac{1}{2}+\frac{1}{2}+\frac{1}{2}$
Fraction that gives length of black line $=\frac{3}{2}$
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Question 382 Marks
How many fractions lie between 0 and 1? Think, discuss with your classmates, and write your answer.
Answer
There are an infinite number of fractions between 0 and 1.
Example: $\frac{3}{5}, \frac{4}{5}, \frac{7}{10} \frac{1}{2}$ etc.
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Question 392 Marks
$\frac{4}{6}$ = ________ = ________ = ________ = ________
Answer
$\begin{aligned} \frac{4}{6} & =\frac{4 \times 2}{6 \times 2}=\frac{4 \times 3}{6 \times 3}=\frac{4 \times 4}{6 \times 4} \\ & =\frac{8}{12}=\frac{12}{18}=\frac{16}{24}\end{aligned}$
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Question 402 Marks
Write two equivalent fractions for $\frac{2}{6}$.
Answer
From the fractional wall we can choose any two fractions that denote the same length as $\frac{2}{6} \cdot \frac{2}{6}=\frac{1}{3}=\frac{3}{9}$
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Question 412 Marks
Now, a unit is divided into 8 equal parts. Write the appropriate fractions in your notebook Solution:Here number line OH is divided into 8 equal parts OA, AB, BC, CD, DE, EF, FG and GH.
Answer

Image
Also, $OA =\frac{1}{8}, OB =\frac{2}{8}, OC =\frac{3}{8}, OH =\frac{8}{8}=1$
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Question 422 Marks
Here, a unit is divided into 5 equal parts. Write the fraction that gives the length of the pink lines in the respective boxes or in your notebook.
Image
Answer
Here number line OT = 1 unit is divided into five equal parts OP, PQ, QR, RS and ST.
Hence length of pink line $O Q=O P+P Q=\frac{1}{5}+\frac{1}{5}=\frac{2}{5}$
Now, length of pink line $OS = OP + PQ + QR + RS =\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=\frac{4}{5}$
Hence, $OQ =\frac{2}{5} OS =\frac{4}{5}$
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Question 432 Marks
Here, the fractional unit is dividing a length of 1 unit into three equal parts. Write the fraction that gives the length of the pink line in the box or in your notebook.
Image
Answer
Here number line OR is divided into three equal parts OP, PQ and QR.
Hence length of pink line $= OP + PQ =\frac{1}{3}+\frac{1}{3}=\frac{2}{3}$
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