Question
Add the following rational numbers: $\frac{3}{-8}\text{ and }\frac{1}{8}$

Answer

$\frac{3}{-8}\text{ and }\frac{1}{8}$
$=\frac{3\times(-1)}{-8\times(-1)}+\frac{1}{8}$
$=\frac{-3}{8}+\frac{1}{8}$
$=\frac{-3+1}{8}=\frac{-2}{8}$
$\frac{-1}{4} ($Dividing by $2)$

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