MCQ
$Ag/AgCl(s) / KCl$ electrode is
  • A
    Reversible $w.r.t$ cation
  • Reversible $w.r.t\, Cl^-$ ion
  • C
    Reversible $w.r.t\, K^+$ ion
  • D
    Reversible $w.r.t\, Ag^+$ ion

Answer

Correct option: B.
Reversible $w.r.t\, Cl^-$ ion
b
Electrode reaction

$AgCl_{(s)} + e^-\to  Ag_{(s)} + Cl^-$

$\therefore $ electrode is reversible $w.r.t.$ chloride ion

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The compound which gets dissolved in water is:
Alkyl and aryl amines are prepared using which of the following reducing agent.
When $0.1\, mole$ of $CoCl_3(NH_3)_5$ is treated with excess of $AgNO_3$, $0.2\, mole$ of $AgCl$ are obtained. The conductivity of solution will correspond to
Which of the following is not a consequence of the Lanthanoid contraction?
Air is a mixture of a number of gases. The major components are oxygen and nitrogen with approximate proportion of $20\%$ is to $79\%$ by volume at $298\ K$ The water is in equilibrium with air at a pressure of $10\ atm$ . At $298\ K$ , if the Henry's law constants for oxygen and nitrogen are $3.30 \times 10^7\ mm$ and $6.51 \times 10^7\  mm$ , respectively, the mole ratio of gases $(O_2 : N_2)$ dissolved in water is about
Assume that a particular amino acid has an isoelectric point of $6.0.$ In a solution at $pH \,1.0$ which of the following species will predominate ?
The density of a solution prepared by dissolving $120\, g$ of urea ( mol. mass $= 60\, u$) in $g$ of water is $1.15\, g /mL .$ The molarity of this solution is : ............ $\mathrm{M}$
A closed vessel with rigid walls contains $1 \ mol$ of ${ }_{92}^{238} U$ and $1 mol$ of air at $298 \ K$. Considering complete decay of ${ }_{92}^{293} U$ to ${ }_{82}^{206} Pb$, the ratio of the final pressure to the initial pressure of the system at $298 \ K$ is
Consider the following sequence of reactions $C{H_3}CH = C{H_2}\xrightarrow[{700\,K}]{{C{l_2}}}A\xrightarrow[{420\,K.12\,atm}]{{N{a_2}C{O_3}}}B\xrightarrow[{\left( {ii} \right)NaOH}]{{\left( i \right)HOCl}}C$ 

Compound $'C'$ is

The addition of $\text{HBr}$ is easiest with: