\( = \frac{{1.43 \times {{10}^{ - 3}}}}{{M.W.}}\,mole/litre = \frac{{143 \times {{10}^{ - 3}}}}{{143 \times 100}}\,mole/litre\)
\( = {10^{ - 5}}\,mole/litre\,\,\,\,\,\,Ksp = {s^2} = {10^{ - 5}} \times {10^{ - 5}} = {10^{ - 10}}\,mole/litre\)
(for $AgCl$ માટે $K_{sp}$ $= 1.8 \times 10^{-10},$ for $PbCl_2$ માટે $ K_{sp}$ $= 1.7 \times 10^{-5}$)