b
b
Mole of \({AgCl}\) precipitated is equal the mole of \({Cl}^{-}\)present in ionization sphere.

\(\left[{Cr}\left({H}_{2} {O}\right)_{3}\left({NH}_{3}\right)_{3}\right] {Cl}_{3} \rightarrow\left[{Cr}\left({H}_{2} {O}\right)_{3}\left({NH}_{3}\right)_{3}\right]^{3+}+3 {Cl}^{-} \overset{AgNO_3}{\rightarrow} AgCl\)

\(1\, mole\) \(\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad1\, mole\) \(\quad\quad\quad\quad3\, mole \quad\quad\quad3\, mole\)

Since none of \({Cl}^{-}\)is present in the co-ordination sphere. Therefore answer is zero.