MCQ
Aluminium chloride exists as dimer, $Al_2Cl_6$ in solid state as well as in soluiton of non-polar solvents such as $C_6H_6.$ When dissolved in water it gives :
  • A
    $Al_2O_3 + 6HCl$
  • B
    $[Al(H_2O)_6]+ 3Cl^-$
  • $[Al(OH)_6]^{3-} + 3HCl$
  • D
    $Al^{3+} + 3Cl^-$

Answer

Correct option: C.
$[Al(OH)_6]^{3-} + 3HCl$
c
Aluminium chloride exists as dimer $\left(\mathrm{Al}_{2} \mathrm{Cl}_{6}\right)$ in a solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives

$\left[\mathrm{Al}(\mathrm{OH})_{6}\right]^{3-}+3 \mathrm{HCl}$

$\mathrm{Al}_{2} \mathrm{Cl}_{6}+12 \mathrm{H}_{2} \mathrm{O} \rightarrow 2\left[\mathrm{Al}(\mathrm{OH})_{6}\right]^{3-}+12 \mathrm{HCl}$

Thus aluminum chloride is hydrolyzed to form the complex ion containing s hydroxide groups.

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