MCQ
Among the following pairs of compounds, the one that illustrates the law of multiple proportions is
- A$N{H_3}$ and $NC{l_3}$
- B${H_2}S$ and $S{O_2}$
- ✓$CuO$ and $ {{\rm{Cu}}_{\rm{2}}}O$
- D$C{S_2}$ and $FeS{O_4}$
Hence, $CuO$ and $Cu _2 O$ form two different compounds in a ratio of $1: 2$ with the fixed weight of oxygen.
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