Question
Among the second period elements the actual ionization enthalpies are in the order $Li < B < Be < C < O < N < F < Ne$. Explain why,
  1. Be has higher $\Delta_{\text{t}}\text{H}$ than B
  2. O has lower $\Delta_{\text{t}}\text{H}$ than N and F?

Answer

  1. During ionization process, the electron that can be expelled from Be (beryllium) – atom is 2s – electron, but the electron that can be expelled from boron is 2p – electron.The attractive force between a 2s – electron and nucleus is higher than between a 2s – electron and nucleus.Thus, the energy required to expel 2s –electron is higher than the energy required to expel 2p –electron.Thus, $\Delta_\text{i}\text{H}$ for Be is higher than $\Delta_\text{i}\text{H}$ than B
  2. In nitrogen, there are three 2p-electrons and all of these 3 occupy 3 distinct atomic orbital. While in oxygen 2 out of 4, 2p – electrons occupy same 2p-orbital, so the repulsion between the electrons in the oxygen atom increases.Thus, the energy required to expel $2^{nd}$ 2p –electron in oxygen atom is higher than the energy required to expel $4^{th}$ 2p –electron in nitrogen atom.Thus, $\Delta_\text{i}\text{H}$ for O is lower than $\Delta_\text{i}\text{H}$ of N.

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