An air capacitor of capacity $C = 10\,\mu F$ is connected to a constant voltage battery of $12\,V$. Now the space between the plates is filled with a liquid of dielectric constant $5$. The charge that flows now from battery to the capacitor is......$\mu C$
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(c) Initially charge on the capacitor $Q = 10 \times 12 = 120\,\mu C$
Finally charge on the capacitor $Q' = (5 \times 10) \times 12 = 600\,\mu C$
So charge supplied by the battery later $ = Q' - Q = 480\,\mu C$
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