MCQ
An alkane (molecular weight $72$) forms only one monochlorinated product. Its formula is
- ✓${(C{H_3})_4}C$
- B$C{H_3}{(C{H_2})_3}C{H_3}$
- C${(C{H_3})_2}CHC{H_2}C{H_3}$
- D


Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(A)$ The acidity of compound $I$ is due to delocalization in the conjugate base.
$(B)$ The conjugate base of compound IV is aromatic.
$(C)$ Compound II becomes more acidic, when it has a $- NO _2$ substituent.
$(D)$ The acidity of compounds follows the order $I > IV > V > II > III$.

