MCQ
During adsorption the $\Delta H$ is $-ve$ and the magnitude of $-ve$ value
- Agoes on increasing
- ✓goes on decreasing
- Cremains same
- Dfirst increase then decreases
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$\Delta E = - 2.0 \times {10^{ - 18}}\,J\left( {\frac{1}{{n_2^2}} - \frac{1}{{n_1^2}}} \right)$
the wavelength of the light that must be absorbed to excite hydrogen electron from level $n\, = 1$ to level $n\, = 2$ will be: $(h\, = 6.625\times10^{-34}\, J\,s,\, C\, = 3\times10^8\, m\,s^{-1})$