An annular ring with inner and outer radii R_{1} and R_{2} is rolling without slipping with a uniform angular speed. The ratio of the forces

Q: An annular ring with inner and outer radii $R_{1}$ and $R_{2}$ is rolling without slipping with a uniform angular speed. The ratio of the forces experienced by the two particles situated on the inner and outer parts of the ring, $\frac{F_{1}}{F_{2}}$ is

b Since $\omega$ is constant, $v$ would also be constant. So, no net force or torque is acting on ring. The force experienced by any particle is only along radial direction, or we can say the centripetal force. The force experienced by inner part, $F_{1}=m \omega^{2} R_{1}$ The force experienced by outer part, $F_{2}=m \omega^{2} R_{2}$ $\frac{F_{1}}{F_{2}}=\frac{R_{1}}{R_{2}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

An annular ring with inner and outer radii $R_{1}$ and $R_{2}$ is rolling without slipping with a uniform angular speed. The ratio of the forces experienced by the two particles situated on the inner and outer parts of the ring, $\frac{F_{1}}{F_{2}}$ is

A$1$
B$ \frac{{{R_1}}}{{{R_2}}} $
C$ \frac{{{R_2}}}{{{R_1}}} $
D$ {\left( {\frac{{{R_1}}}{{{R_2}}}} \right)^2} $

AIEEE 2005, Medium

STD 11 Science
NEET
STD 11 - 4.2. friction
Physics

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