An arbitrary shaped closed coil is made of a wire of length $L$ and a current $I$ ampere is flowing in it. If the plane of the coil is perpendicular to magnetic field $\mathop B\limits^ \to $, the force on the coil is
A$Zero$
B$IBL$
C$2IBL$
D$\frac{1}{2}IBL$
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A$Zero$
a (a) As shown in figure, since $\overrightarrow L = 0$
Hence according to $\vec F = i(\vec L \times \vec B)$ $==>$ $\vec F = 0$
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